Area of Path and Verandah
Area of Path and Verandah
Area of Path & Verandah:
It is observed that in square or rectangular gardens or parks. Some space in the form of path is left inside or outside or in between as cross paths.
Illustration: A footpath of uniform width 5 m runs round the inside of a rectangular park 38 m long and 32 m wide. Find the area of the path.
Solution: Let ABCD be the rectangular park and PQRS be the internal boundaries of the path.
We have, Length AB= 38 m and Breadth BC= 32 m:
Thus, Area of rectangle ABCD = AB BC = 38 m
32 m = 1216
Now, Length PQ = 38 m - 5 m - 5 m = 28 m and Breadth QR = 32 m - 5 m - 5 m = 22m
Area of rectangle PQRS = PQ RS = 28 m
22 m = 616
Area of footpath = Area of rectangle ABCD - Area of rectangle PQRS = 1216 - 616=600
Thus, Area of footpath =600
The area of the crossroads = Area of the two colored rectangles - Area of the red colored rectangle at the centre.
We are subtracting the area of the rectangle because we are taking it into consideration two times.
If the cost of paving a foot path on all the sides surrounding a park with sides 40 m and 36 m at the rate of Rs. 4 per sq. meter is Rs. 3440, what is the width of the foot path? | |||
| Right Option : B | |||
| View Explanation | |||
A painting is painted on a cardboard 19 cm and 14 cm wide , such that there is a margin of 1.5 cm along each of its sides .Find the total area of the margin. | |||
| Right Option : A | |||
| View Explanation | |||
A square plot has side 100 m. A path 5 m wide runs breadth wise across the ground in the middle. Find the area of the path. | |||
| Right Option : A | |||
| View Explanation | |||
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